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They
NP
did
(S[dcl]\NP)/(S[b]\NP)
n't
(S\NP)\(S\NP)
(S[dcl]\NP)/(S[b]\NP)
<
1
×
know
(S[b]\NP)/S[qem]
when
S[qem]/S[dcl]
they
NP
'd
(S[dcl]\NP)/(S[b]\NP)
be
(S[b]\NP)/(S[adj]\NP)
back
S[adj]\NP
.
.
S[adj]\NP
.
S[b]\NP
>
0
S[dcl]\NP
>
0
S[dcl]
<
0
S[qem]
>
0
S[b]\NP
>
0
S[dcl]\NP
>
0
S[dcl]
<
0
<div class="der"> <table class="constituent binaryrule" data-cat="S[dcl]"> <tr class="daughters"> <td class="daughter daughter-left"><table class="constituent lex" data-token="They" data-from="0" data-to="4" data-cat="NP"> <tr><td class="token">They</td></tr> <tr><td class="cat" tabindex="0">NP</td></tr> <tr><td class="span-swiper"> </td></tr> </table></td> <td class="daughter daughter-right"><table class="constituent binaryrule" data-cat="S[dcl]\NP"> <tr class="daughters"> <td class="daughter daughter-left"><table class="constituent binaryrule" data-cat="(S[dcl]\NP)/(S[b]\NP)"> <tr class="daughters"> <td class="daughter daughter-left"><table class="constituent lex" data-token="did" data-from="5" data-to="8" data-cat="(S[dcl]\NP)/(S[b]\NP)"> <tr><td class="token">did</td></tr> <tr><td class="cat" tabindex="0">(S[dcl]\NP)/(S[b]\NP)</td></tr> <tr><td class="span-swiper"> </td></tr> </table></td> <td class="daughter daughter-right"><table class="constituent lex" data-token="n't" data-from="8" data-to="11" data-cat="(S\NP)\(S\NP)"> <tr><td class="token">n't</td></tr> <tr><td class="cat" tabindex="0">(S\NP)\(S\NP)</td></tr> <tr><td class="span-swiper"> </td></tr> </table></td> </tr> <tr><td colspan="2" class="rulecat"><div class="rulecat"> <div class="cat">(S[dcl]\NP)/(S[b]\NP)</div> <div class="rule" title="Backward Crossed Composition">< <sup>1</sup><sub>×</sub> </div> </div></td></tr> </table></td> <td class="daughter daughter-right"><table class="constituent binaryrule" data-cat="S[b]\NP"> <tr class="daughters"> <td class="daughter daughter-left"><table class="constituent lex" data-token="know" data-from="12" data-to="16" data-cat="(S[b]\NP)/S[qem]"> <tr><td class="token">know</td></tr> <tr><td class="cat" tabindex="0">(S[b]\NP)/S[qem]</td></tr> <tr><td class="span-swiper"> </td></tr> </table></td> <td class="daughter daughter-right"><table class="constituent binaryrule" data-cat="S[qem]"> <tr class="daughters"> <td class="daughter daughter-left"><table class="constituent lex" data-token="when" data-from="17" data-to="21" data-cat="S[qem]/S[dcl]"> <tr><td class="token">when</td></tr> <tr><td class="cat" tabindex="0">S[qem]/S[dcl]</td></tr> <tr><td class="span-swiper"> </td></tr> </table></td> <td class="daughter daughter-right"><table class="constituent binaryrule" data-cat="S[dcl]"> <tr class="daughters"> <td class="daughter daughter-left"><table class="constituent lex" data-token="they" data-from="22" data-to="26" data-cat="NP"> <tr><td class="token">they</td></tr> <tr><td class="cat" tabindex="0">NP</td></tr> <tr><td class="span-swiper"> </td></tr> </table></td> <td class="daughter daughter-right"><table class="constituent binaryrule" data-cat="S[dcl]\NP"> <tr class="daughters"> <td class="daughter daughter-left"><table class="constituent lex" data-token="'d" data-from="26" data-to="28" data-cat="(S[dcl]\NP)/(S[b]\NP)"> <tr><td class="token">'d</td></tr> <tr><td class="cat" tabindex="0">(S[dcl]\NP)/(S[b]\NP)</td></tr> <tr><td class="span-swiper"> </td></tr> </table></td> <td class="daughter daughter-right"><table class="constituent binaryrule" data-cat="S[b]\NP"> <tr class="daughters"> <td class="daughter daughter-left"><table class="constituent lex" data-token="be" data-from="29" data-to="31" data-cat="(S[b]\NP)/(S[adj]\NP)"> <tr><td class="token">be</td></tr> <tr><td class="cat" tabindex="0">(S[b]\NP)/(S[adj]\NP)</td></tr> <tr><td class="span-swiper"> </td></tr> </table></td> <td class="daughter daughter-right"><table class="constituent binaryrule" data-cat="S[adj]\NP"> <tr class="daughters"> <td class="daughter daughter-left"><table class="constituent lex" data-token="back" data-from="32" data-to="36" data-cat="S[adj]\NP"> <tr><td class="token">back</td></tr> <tr><td class="cat" tabindex="0">S[adj]\NP</td></tr> <tr><td class="span-swiper"> </td></tr> </table></td> <td class="daughter daughter-right"><table class="constituent lex" data-token="." data-from="36" data-to="37" data-cat="."> <tr><td class="token">.</td></tr> <tr><td class="cat" tabindex="0">.</td></tr> <tr><td class="span-swiper"> </td></tr> </table></td> </tr> <tr><td colspan="2" class="rulecat"><div class="rulecat"> <div class="cat">S[adj]\NP</div> <div class="rule" title="Remove Punctuation">.</div> </div></td></tr> </table></td> </tr> <tr><td colspan="2" class="rulecat"><div class="rulecat"> <div class="cat">S[b]\NP</div> <div class="rule" title="Forward Application">> <sup>0</sup> </div> </div></td></tr> </table></td> </tr> <tr><td colspan="2" class="rulecat"><div class="rulecat"> <div class="cat">S[dcl]\NP</div> <div class="rule" title="Forward Application">> <sup>0</sup> </div> </div></td></tr> </table></td> </tr> <tr><td colspan="2" class="rulecat"><div class="rulecat"> <div class="cat">S[dcl]</div> <div class="rule" title="Backward Application">< <sup>0</sup> </div> </div></td></tr> </table></td> </tr> <tr><td colspan="2" class="rulecat"><div class="rulecat"> <div class="cat">S[qem]</div> <div class="rule" title="Forward Application">> <sup>0</sup> </div> </div></td></tr> </table></td> </tr> <tr><td colspan="2" class="rulecat"><div class="rulecat"> <div class="cat">S[b]\NP</div> <div class="rule" title="Forward Application">> <sup>0</sup> </div> </div></td></tr> </table></td> </tr> <tr><td colspan="2" class="rulecat"><div class="rulecat"> <div class="cat">S[dcl]\NP</div> <div class="rule" title="Forward Application">> <sup>0</sup> </div> </div></td></tr> </table></td> </tr> <tr><td colspan="2" class="rulecat"><div class="rulecat"> <div class="cat">S[dcl]</div> <div class="rule" title="Backward Application">< <sup>0</sup> </div> </div></td></tr> </table> </div>
Use with
der.css
.
\begin{tikzpicture}[ampersand replacement=\&] \matrix [column sep=9pt] at (0, 0) { \lexnode*{idm8}{They}{\catNP}{} \& \lexnode*{idm34}{did}{(\catS[dcl]\?\catNP)/(\catS[b]\?\catNP)}{} \& \lexnode*{idm48}{n't}{(\catS\?\catNP)\?(\catS\?\catNP)}{} \& \lexnode*{idm69}{know}{(\catS[b]\?\catNP)/\catS[qem]}{} \& \lexnode*{idm86}{when}{\catS[qem]/\catS[dcl]}{} \& \lexnode*{idm101}{they}{\catNP}{} \& \lexnode*{idm116}{'d}{(\catS[dcl]\?\catNP)/(\catS[b]\?\catNP)}{} \& \lexnode*{idm137}{be}{(\catS[b]\?\catNP)/(\catS[adj]\?\catNP)}{} \& \lexnode*{idm158}{back}{\catS[adj]\?\catNP}{} \& \lexnode*{idm168}{.}{\cat.}{} \\ }; \binnode*{idm23}{idm34-cat}{idm48-cat}{\BXC{1}}{(\catS[dcl]\?\catNP)/(\catS[b]\?\catNP)}{} \binnode*{idm151}{idm158-cat}{idm168-cat}{.}{\catS[adj]\?\catNP}{} \binnode*{idm130}{idm137-cat}{idm151}{\FC{0}}{\catS[b]\?\catNP}{} \binnode*{idm109}{idm116-cat}{idm130}{\FC{0}}{\catS[dcl]\?\catNP}{} \binnode*{idm96}{idm101-cat}{idm109}{\BC{0}}{\catS[dcl]}{} \binnode*{idm81}{idm86-cat}{idm96}{\FC{0}}{\catS[qem]}{} \binnode*{idm62}{idm69-cat}{idm81}{\FC{0}}{\catS[b]\?\catNP}{} \binnode*{idm16}{idm23}{idm62}{\FC{0}}{\catS[dcl]\?\catNP}{} \binnode*{idm3}{idm8-cat}{idm16}{\BC{0}}{\catS[dcl]}{} \end{tikzpicture}
Use with
ccgsym.sty
and
tikzlibraryccgder.code.tex
.
Translations
rus
Они не знали, когда вернутся.