Sentence


Parse

This
NP
 
could
(S[dcl]\NP)/(S[b]\NP)
 
come
S[b]\NP
 
S[dcl]\NP
> 0
in
((S\NP)\(S\NP))/NP
 
handy
N
 
NP
*
.
.
 
NP
.
(S\NP)\(S\NP)
> 0
S[dcl]\NP
< 0
S[dcl]
< 0

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