Sentence


Parse

This
NP/N
 
report
N
 
NP
> 0
leaves
((S[dcl]\NP)/(S[to]\NP))/NP
 
a
NP/N
 
lot
N
 
NP
> 0
(S[dcl]\NP)/(S[to]\NP)
> 0
to
(S[to]\NP)/(S[b]\NP)
 
be
(S[b]\NP)/(S[pss]\NP)
 
desired
S[pss]\NP
 
S[b]\NP
> 0
.
.
 
S[b]\NP
.
S[to]\NP
> 0
S[dcl]\NP
> 0
S[dcl]
< 0

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