CCGWeb - This doesn't look good at all.

This

does

(S[dcl]\NP)/(S[b]\NP)

n't

(S\NP)\(S\NP)

(S[dcl]\NP)/(S[b]\NP)

< ¹_×

look

(S[b]\NP)/(S[adj]\NP)

good

S[adj]\NP

S[b]\NP

> ⁰

((S\NP)\(S\NP))/NP

all

(S\NP)\(S\NP)

> ⁰

(S\NP)\(S\NP)

S[b]\NP

< ⁰

S[dcl]\NP

> ⁰

S[dcl]

< ⁰

 <div class="der">
<table class="constituent binaryrule" data-cat="S[dcl]">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent lex" data-token="This" data-from="0" data-to="4" data-cat="NP">
<tr><td class="token">This</td></tr>
<tr><td class="cat" tabindex="0">NP</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent binaryrule" data-cat="S[dcl]\NP">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent binaryrule" data-cat="(S[dcl]\NP)/(S[b]\NP)">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent lex" data-token="does" data-from="5" data-to="9" data-cat="(S[dcl]\NP)/(S[b]\NP)">
<tr><td class="token">does</td></tr>
<tr><td class="cat" tabindex="0">(S[dcl]\NP)/(S[b]\NP)</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent lex" data-token="n't" data-from="9" data-to="12" data-cat="(S\NP)\(S\NP)">
<tr><td class="token">n't</td></tr>
<tr><td class="cat" tabindex="0">(S\NP)\(S\NP)</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">(S[dcl]\NP)/(S[b]\NP)</div>
<div class="rule" title="Backward Crossed Composition">&lt; <sup>1</sup><sub>×</sub>
</div>
</div></td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent binaryrule" data-cat="S[b]\NP">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent binaryrule" data-cat="S[b]\NP">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent lex" data-token="look" data-from="13" data-to="17" data-cat="(S[b]\NP)/(S[adj]\NP)">
<tr><td class="token">look</td></tr>
<tr><td class="cat" tabindex="0">(S[b]\NP)/(S[adj]\NP)</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent lex" data-token="good" data-from="18" data-to="22" data-cat="S[adj]\NP">
<tr><td class="token">good</td></tr>
<tr><td class="cat" tabindex="0">S[adj]\NP</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">S[b]\NP</div>
<div class="rule" title="Forward Application">&gt; <sup>0</sup>
</div>
</div></td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent binaryrule" data-cat="(S\NP)\(S\NP)">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent binaryrule" data-cat="(S\NP)\(S\NP)">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent lex" data-token="at" data-from="23" data-to="25" data-cat="((S\NP)\(S\NP))/NP">
<tr><td class="token">at</td></tr>
<tr><td class="cat" tabindex="0">((S\NP)\(S\NP))/NP</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent lex" data-token="all" data-from="26" data-to="29" data-cat="NP">
<tr><td class="token">all</td></tr>
<tr><td class="cat" tabindex="0">NP</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">(S\NP)\(S\NP)</div>
<div class="rule" title="Forward Application">&gt; <sup>0</sup>
</div>
</div></td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent lex" data-token="." data-from="29" data-to="30" data-cat=".">
<tr><td class="token">.</td></tr>
<tr><td class="cat" tabindex="0">.</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">(S\NP)\(S\NP)</div>
<div class="rule" title="Remove Punctuation">.</div>
</div></td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">S[b]\NP</div>
<div class="rule" title="Backward Application">&lt; <sup>0</sup>
</div>
</div></td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">S[dcl]\NP</div>
<div class="rule" title="Forward Application">&gt; <sup>0</sup>
</div>
</div></td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">S[dcl]</div>
<div class="rule" title="Backward Application">&lt; <sup>0</sup>
</div>
</div></td></tr>
</table> </div>

Use with der.css.

\begin{tikzpicture}[ampersand replacement=\&]
	\matrix [column sep=9pt] at (0, 0) {
		\lexnode*{idm8}{This}{\catNP}{} \&
		\lexnode*{idm34}{does}{(\catS[dcl]\?\catNP)/(\catS[b]\?\catNP)}{} \&
		\lexnode*{idm48}{n't}{(\catS\?\catNP)\?(\catS\?\catNP)}{} \&
		\lexnode*{idm76}{look}{(\catS[b]\?\catNP)/(\catS[adj]\?\catNP)}{} \&
		\lexnode*{idm90}{good}{\catS[adj]\?\catNP}{} \&
		\lexnode*{idm122}{at}{((\catS\?\catNP)\?(\catS\?\catNP))/\catNP}{} \&
		\lexnode*{idm138}{all}{\catNP}{} \&
		\lexnode*{idm146}{.}{\cat.}{} \\
	};
	\binnode*{idm23}{idm34-cat}{idm48-cat}{\BXC{1}}{(\catS[dcl]\?\catNP)/(\catS[b]\?\catNP)}{}
	\binnode*{idm69}{idm76-cat}{idm90-cat}{\FC{0}}{\catS[b]\?\catNP}{}
	\binnode*{idm111}{idm122-cat}{idm138-cat}{\FC{0}}{(\catS\?\catNP)\?(\catS\?\catNP)}{}
	\binnode*{idm100}{idm111}{idm146-cat}{.}{(\catS\?\catNP)\?(\catS\?\catNP)}{}
	\binnode*{idm62}{idm69}{idm100}{\BC{0}}{\catS[b]\?\catNP}{}
	\binnode*{idm16}{idm23}{idm62}{\FC{0}}{\catS[dcl]\?\catNP}{}
	\binnode*{idm3}{idm8-cat}{idm16}{\BC{0}}{\catS[dcl]}{}
\end{tikzpicture}

Use with ccgsym.sty and tikzlibraryccgder.code.tex.

Sentence

Parse

Translations