Sentence


Parse

This
NP
 
is
(S[dcl]\NP)/(S[adj]\NP)
 
enough
(S[adj]\NP)/PP
 
for
PP/NP
 
me
NP
 
.
.
 
NP
.
PP
> 0
S[adj]\NP
> 0
S[dcl]\NP
> 0
S[dcl]
< 0

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