Sentence


Parse

Tom
N
 
NP
*
is
(S[dcl]\NP)/(S[adj]\NP)
 
old
(S[adj]\NP)/(S[to]\NP)
 
enough
(S[adj]\NP)\(S[adj]\NP)
 
(S[adj]\NP)/(S[to]\NP)
< 1×
to
(S[to]\NP)/(S[b]\NP)
 
be
(S[b]\NP)/NP
 
your
NP/(N/PP)
 
grandfather
N/PP
 
NP
> 0
.
.
 
NP
.
S[b]\NP
> 0
S[to]\NP
> 0
S[adj]\NP
> 0
S[dcl]\NP
> 0
S[dcl]
< 0

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