Sentence


Parse

Tom
N
 
NP
*
seems
(S[dcl]\NP)/(S[to]\NP)
 
to
(S[to]\NP)/(S[b]\NP)
 
be
(S[b]\NP)/(S[ng]\NP)
 
looking
(S[ng]\NP)/PP
 
for
PP/NP
 
something
NP
 
PP
> 0
S[ng]\NP
> 0
.
.
 
S[ng]\NP
.
S[b]\NP
> 0
S[to]\NP
> 0
S[dcl]\NP
> 0
S[dcl]
< 0

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