Sentence


Parse

We
NP
 
look
((S[dcl]\NP)/PP)/(S[adj]\NP)
 
forward
(S\NP)\(S\NP)
 
((S[dcl]\NP)/PP)/(S[adj]\NP)
< n×
to
PP/(S[ng]\NP)
 
seeing
(S[ng]\NP)/NP
 
you
NP
 
S[ng]\NP
> 0
PP
> 0
(S[X]\NP)\((S[X]\NP)/PP)
T <
(S[dcl]\NP)/(S[adj]\NP)
< 1×
here
S[adj]\NP
 
.
.
 
S[adj]\NP
.
S[dcl]\NP
> 0
S[dcl]
< 0

Use with der.css.

Use with ccgsym.sty and tikzlibraryccgder.code.tex.