Sentence


Parse

We
NP
 
need
(S[dcl]\NP)/(S[to]\NP)
 
to
(S[to]\NP)/(S[b]\NP)
 
look
(S[b]\NP)/PP
 
for
PP/NP
 
a
NP/N
 
gas
N/N
 
station
N
 
N
> 0
NP
> 0
PP
> 0
S[b]\NP
> 0
S[to]\NP
> 0
S[dcl]\NP
> 0
because
((S\NP)\(S\NP))/S[dcl]
 
this
NP/N
 
car
N
 
NP
> 0
will
(S[dcl]\NP)/(S[b]\NP)
 
soon
(S\NP)\(S\NP)
 
(S[dcl]\NP)/(S[b]\NP)
< 1×
run
S[b]\NP
 
out
((S\NP)\(S\NP))/PP
 
of
PP/NP
 
gas
N
 
NP
*
PP
> 0
(S\NP)\(S\NP)
> 0
S[b]\NP
< 0
S[dcl]\NP
> 0
S[dcl]
< 0
(S\NP)\(S\NP)
> 0
S[dcl]\NP
< 0
S[dcl]
< 0
.
.
 
S[dcl]
.

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