Sentence


Parse

We
NP
 
need
(S[dcl]\NP)/NP
 
your
NP/(N/PP)
 
help
N/PP
 
finding
(S[ng]\NP)/NP
 
her
NP
 
S[ng]\NP
> 0
N\N
*
.
.
 
N\N
.
N/PP
< 1×
NP
> 0
S[dcl]\NP
> 0
S[dcl]
< 0

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