Sentence


Parse

Would
(S[q]/(S[b]\NP))/NP
 
you
NP
 
S[q]/(S[b]\NP)
> 0
rather
S\S
 
S[q]/(S[b]\NP)
< 1×
be
(S[b]\NP)/(S[adj]\NP)
 
rich
S[adj]\NP
 
or
conj
 
famous
S[adj]\NP
 
(S[adj]\NP)\(S[adj]\NP)
?
.
 
(S[adj]\NP)\(S[adj]\NP)
.
S[adj]\NP
< 0
S[b]\NP
> 0
S[q]
> 0

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