Sentence


Parse

You
NP
 
can
(S[dcl]\NP)/(S[b]\NP)
 
do
(S[b]\NP)/NP
 
it
NP
 
(S[X]\NP)\((S[X]\NP)/NP)
T <
,
,
 
ca
(S[dcl]\NP)/(S[b]\NP)
 
n't
(S\NP)\(S\NP)
 
(S[dcl]\NP)/(S[b]\NP)
< 1×
you
NP
 
?
.
 
NP
.
(S[X]\NP)\((S[X]\NP)/NP)
T <
(S[dcl]\NP)\((S[b]\NP)/NP)
> 1×
((S[dcl]\NP)\((S[b]\NP)/NP))\((S[dcl]\NP)\((S[b]\NP)/NP))
(S[b]\NP)\((S[b]\NP)/NP)
< 0
S[b]\NP
< 0
S[dcl]\NP
> 0
S[dcl]
< 0

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