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You
NP
 
know
(S[dcl]\NP)/S[em]
 
that
S[em]/S[dcl]
 
I
NP
 
'd
(S[dcl]\NP)/(S[b]\NP)
 
never
(S\NP)\(S\NP)
 
(S[dcl]\NP)/(S[b]\NP)
< 1×
do
(S[b]\NP)/NP
 
that
NP/N
 
kind
N/PP
 
of
PP/NP
 
thing
N
 
NP
*
.
.
 
NP
.
PP
> 0
N
> 0
NP
> 0
S[b]\NP
> 0
S[dcl]\NP
> 0
S[dcl]
< 0
S[em]
> 0
S[dcl]\NP
> 0
S[dcl]
< 0

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