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Your
NP/(N/PP)
 
job
N/PP
 
NP
> 0
is
(S[dcl]\NP)/(S[adj]\NP)
 
n't
(S\NP)\(S\NP)
 
(S[dcl]\NP)/(S[adj]\NP)
< 1×
easy
S[adj]\NP
 
.
.
 
S[adj]\NP
.
S[dcl]\NP
> 0
S[dcl]
< 0

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