Sentence


Parse

Fais
N
 
NP
*
NP/(NP\NP)
T >
ce
(NP\NP)/NP
 
NP/NP
> 1
que
(S[dcl]\NP)\NP
 
(S[dcl]\NP)/NP
< 1×
tu
NP
 
S[dcl]/(S[dcl]\NP)
T >
as
(S[dcl]\NP)/(S[dcl]\NP)
 
à
N/N
 
faire
N
 
N
> 0
NP
*
(S[dcl]\NP)\((S[dcl]\NP)/NP)
T <
(S[dcl]\NP)\((S[dcl]\NP)/NP)
> 1×
S[dcl]\((S[dcl]\NP)/NP)
> 1×
S[dcl]
< 0
.
S[dcl]\S[dcl]
 
S[dcl]
< 0

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