Sentence


Parse

J'
S[dcl]/PP
 
ai
PP/NP
 
oublié
N/N
 
de
N/N
 
t'
N
 
N
> 0
NP
*
S[dcl]/(S[dcl]\NP)
T >
envoyer
(S[dcl]\NP)/NP
 
S[dcl]/NP
> 1
N\N
*
N/N
< 1×
un
NP/N
 
courriel
N
 
N\(N/N)
T <
NP\(N/N)
> 1×
NP
< 0
PP
> 0
S[dcl]
> 0
.
S[dcl]\S[dcl]
 
S[dcl]
< 0

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