Sentence


Parse

J'
N/PP
 
ai
PP/NP
 
fait
N
 
NP
*
PP
> 0
N
> 0
NP
*
ce
(S[dcl]\NP)/(S[dcl]\NP)
 
que
(S[dcl]\NP)/(S[dcl]\NP)
 
j'
(S[dcl]\NP)/PP
 
ai
PP/NP
 
pu
N
 
NP
*
PP
> 0
S[dcl]\NP
> 0
S[dcl]\NP
> 0
S[dcl]\NP
> 0
S[dcl]
< 0
.
S[dcl]\S[dcl]
 
S[dcl]
< 0

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