Sentence


Parse

Le
NP/N
 
bruit
(S[dcl]\NP)/NP
 
devient
N/N
 
de
N/N
 
plus
N
 
N
> 0
N
> 0
NP
*
S[dcl]\NP
> 0
S[dcl]/N
< 1×
en
N/N
 
plus
N/N
 
fort
N
 
N
> 0
N
> 0
S[dcl]
> 0
.
S[dcl]\S[dcl]
 
S[dcl]
< 0

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