Sentence


Parse

Nous
N
 
avons
N
 
NP
*
S[dcl]/(S[dcl]\NP)
T >
cela
(S[dcl]\NP)/NP
 
en
((S[dcl]\NP)\(S[dcl]\NP))/NP
 
commun
N
 
NP
*
(S[dcl]\NP)\(S[dcl]\NP)
> 0
(S[dcl]\NP)/NP
< 1×
S[dcl]/NP
> 1
.
S[dcl]\S[dcl]
 
S[dcl]/NP
< 1×
N\N
*
N
< 0
NP
*

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