Sentence


Parse

Oh
N
 
non
S[q]/(S[b]\NP)
 
!
(S[b]\NP)/NP
 
Qu'
NP/N
 
est
N\N
 
-
N\N
 
N\N
< 1
ce
N/N
 
que
(NP\NP)/NP
 
je
NP
 
NP\NP
> 0
vais
NP/N
 
dire
(S[ng]\NP)/NP
 
à
N/N
 
Tom
N
 
N
> 0
NP\(NP/N)
T <
(S[ng]\NP)\(NP/N)
> 1×
S[ng]\NP
< 0
S[ng]\NP
< 1
N\N
*
N\N
> 1×
N\N
< 1
NP\N
> 1×
(S[b]\NP)\N
> 1×
S[q]\N
> 1×
S[q]
< 0
?
S[q]\S[q]
 
S[q]
< 0

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