Sentence


Parse

On
S[dcl]/PP
 
a
PP/NP
 
perdu
NP/N
 
beaucoup
N/N
 
de
N/N
 
temps
N
 
N
> 0
N
> 0
NP
> 0
PP
> 0
S[dcl]
> 0
.
S[dcl]\S[dcl]
 
S[dcl]
< 0

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