Sentence


Parse

On
S[dcl]/S[dcl]
 
dirait
(S[dcl]\NP)/NP
 
que
N/NP
 
c'
NP/N
 
est
N
 
NP
> 0
N
> 0
NP
*
S[dcl]/(S[dcl]\NP)
T >
juste
N
 
NP
*
(S[dcl]\NP)\((S[dcl]\NP)/NP)
T <
S[dcl]\((S[dcl]\NP)/NP)
> 1×
S[dcl]
< 0
.
S[dcl]\S[dcl]
 
S[dcl]
< 0
S[dcl]
> 0

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