Sentence


Parse

Parler
S[dcl]/NP
 
l'
NP/N
 
anglais
N
 
est
N\N
 
N
< 0
difficile
N\N
 
N
< 0
NP
> 0
S[dcl]
> 0
.
S[dcl]\S[dcl]
 
S[dcl]
< 0

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