Sentence


Parse

Puis
S[q]/NP
 
-
N
 
je
N
 
NP
*
S[dcl]/(S[dcl]\NP)
T >
disposer
(S[dcl]\NP)/NP
 
S[dcl]/NP
> 1
N\N
*
N
< 0
d'
(S[ng]\NP)/NP
 
un
NP/N
 
horaire
N
 
NP
> 0
S[ng]\NP
> 0
N\N
*
N
< 0
NP
*
S[q]
> 0
?
S[q]\S[q]
 
S[q]
< 0

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