Sentence


Parse

È
S[dcl]/PP
 
di
PP/NP
 
S[dcl]/NP
> 1
rigore
S[ng]\NP
 
S[dcl]/S[dcl]
*
l'
NP/N
 
abito
N
 
da
(N\N)/NP
 
sera
N
 
NP
*
N\N
> 0
N
< 0
NP
> 0
S[dcl]\(S[dcl]/NP)
T <
S[dcl]\(S[dcl]/NP)
> 1×
S[dcl]
< 0
.
S[dcl]\S[dcl]
 
S[dcl]
< 0

Use with der.css.

Use with ccgsym.sty and tikzlibraryccgder.code.tex.