Sentence


Parse

Mary
N
 
mi
NP
 
S[dcl]/(S[dcl]\NP)
T >
ha
(S[dcl]\NP)/(S[b]\NP)
 
detto
(S[b]\NP)/S[em]
 
che
S[em]/S[dcl]
 
ha
NP
 
S[dcl]/(S[dcl]\NP)
T >
vinto
(S[dcl]\NP)/NP
 
S[dcl]/NP
> 1
.
S[dcl]\S[dcl]
 
S[dcl]/NP
< 1×
S[em]/NP
> 1
(S[b]\NP)/NP
> 1
(S[dcl]\NP)/NP
> 1
S[dcl]/NP
> 1
N\N
*
N
< 0
NP
*

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