Sentence


Parse

Noi
NP
 
ci
(S[dcl]\NP)/(S[dcl]\NP)
 
aspettavamo
(S[dcl]\NP)/S[em]
 
che
S[em]/S[dcl]
 
Takahashi
N
 
NP
*
si
(S[dcl]\NP)/(S[adj]\NP)
 
ubriacasse
S[adj]\NP
 
S[dcl]\NP
> 0
e
((S[dcl]\NP)\(S[dcl]\NP))/(S[dcl]\NP)
 
dicesse
(S[dcl]\NP)/NP
 
alcune
NP/N
 
cose
N
 
strane
N\N
 
N
< 0
N/(N\N)
T >
NP/(N\N)
> 1
,
NP\NP
 
NP/(N\N)
< 1×
(S[dcl]\NP)/(N\N)
> 1
ma
(S[dcl]\S[dcl])/S[dcl]
 
ha
NP
 
finito
S[dcl]\NP
 
per
((S[dcl]\NP)\(S[dcl]\NP))/(S[b]\NP)
 
non
NP/N
 
bere
(S[b]\NP)/NP
 
troppo
N
 
NP\(NP/N)
T <
(S[b]\NP)\(NP/N)
> 1×
S[b]\NP
< 0
,
(S[b]\NP)\(S[b]\NP)
 
S[b]\NP
< 0
(S[dcl]\NP)\(S[dcl]\NP)
> 0
S[dcl]\NP
< 0
S[dcl]
< 0
S[dcl]\S[dcl]
> 0
(S[dcl]\NP)/(N\N)
< n
quindi
(S[dcl]\NP)/(S[dcl]\NP)
 
non
(S[dcl]/NP)/(S[dcl]\NP)
 
è
S[dcl]/S[dcl]
 
stato
(S[dcl]\NP)/(S[adj]\NP)
 
interessante
S[adj]\NP
 
S[dcl]\NP
> 0
S[dcl]\NP
> 1×
(S[dcl]\NP)\((S[dcl]\NP)/(S[dcl]\NP))
T <
(S[dcl]/NP)\((S[dcl]\NP)/(S[dcl]\NP))
> 1×
S[dcl]/NP
< 0
N\N
*
S[dcl]\NP
> 0
(S[dcl]\NP)\(S[dcl]\NP)
> 0
S[dcl]\NP
< 0
S[dcl]
< 0
.
S[dcl]\S[dcl]
 
S[dcl]
< 0
S[em]
> 0
S[dcl]\NP
> 0
S[dcl]\NP
> 0
S[dcl]
< 0

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