Sentence


Parse

Qualcuno
NP
 
potrebbe
(S[dcl]\NP)/NP
 
,
(S[dcl]\NP)\(S[dcl]\NP)
 
(S[dcl]\NP)/NP
< 1×
per
((S[dcl]\NP)\(S[dcl]\NP))/NP
 
favore
N
 
NP
*
,
NP\NP
 
NP
< 0
aprire
NP\NP
 
NP
< 0
(S[dcl]\NP)\(S[dcl]\NP)
> 0
(S[dcl]\NP)/NP
< 1×
la
NP/N
 
porta
N
 
NP
> 0
?
NP\NP
 
NP
< 0
S[dcl]\NP
> 0
S[dcl]
< 0

Use with der.css.

Use with ccgsym.sty and tikzlibraryccgder.code.tex.