Sentence


Parse

Sta
NP
 
mettendo
S[ng]\NP
 
a
(S[ng]\NP)\(S[ng]\NP)
 
S[ng]\NP
< 0
S[dcl]/S[dcl]
*
dura
N/N
 
prova
(S[dcl]\NP)/NP
 
la
NP/N
 
mia
N/N
 
pazienza
N
 
N
> 0
N\(N/N)
T <
NP\(N/N)
> 1×
(S[dcl]\NP)\(N/N)
> 1×
S[dcl]\NP
< 0
S[dcl]\NP
> 1×
S[dcl]
< 0
.
S[dcl]\S[dcl]
 
S[dcl]
< 0

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