Sentence


Parse

Un
NP/N
 
bicchiere
N
 
d'
(S[dcl]\NP)/NP
 
acqua
N
 
NP
*
S[dcl]/(S[dcl]\NP)
T >
,
(S[dcl]/(S[dcl]\NP))\(S[dcl]/(S[dcl]\NP))
 
S[dcl]/(S[dcl]\NP)
< 0
per
((S[dcl]\NP)\(S[dcl]\NP))/NP
 
favore
N
 
NP
*
.
NP\NP
 
NP
< 0
(S[dcl]\NP)\(S[dcl]\NP)
> 0
S[dcl]\(S[dcl]\NP)
> 1×
S[dcl]/NP
< 1×
N\N
*
N
< 0
NP
> 0

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