Sentence


Parse

Bijt
S[dcl]/NP
 
op
S[dcl]/S[dcl]
 
je
NP/N
 
tong
N
 
NP
> 0
S[dcl]\(S[dcl]/NP)
T <
S[dcl]\(S[dcl]/NP)
> 1×
S[dcl]
< 0
.
S[dcl]\S[dcl]
 
S[dcl]
< 0

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