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Sentence
ara
bul
dan
eng
est
deu
fra
hin
ind
ita
kan
ltz
mar
nld
pol
por
ron
rus
spa
srp
tur
urd
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Parse
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Het
NP
is
(S[dcl]\NP)/NP
drie
N/N
jaar
N
N
>
0
NP
*
S[dcl]\NP
>
0
sinds
((S[dcl]\NP)\(S[dcl]\NP))/S[dcl]
Tom
N
NP
*
Boston
N
NP
*
heeft
(S[dcl]\NP)/(S[pt]\NP)
verlaten
(S[pt]\NP)\NP
(S[dcl]\NP)\NP
>
1
×
S[dcl]\NP
<
0
S[dcl]
<
0
.
S[dcl]\S[dcl]
S[dcl]
<
0
(S[dcl]\NP)\(S[dcl]\NP)
>
0
S[dcl]\NP
<
0
S[dcl]
<
0
<div class="der"> <table class="constituent binaryrule" data-cat="S[dcl]"> <tr class="daughters"> <td class="daughter daughter-left"><table class="constituent lex" data-token="Het" data-from="0" data-to="3" data-cat="NP"> <tr><td class="token">Het</td></tr> <tr><td class="cat" tabindex="0">NP</td></tr> <tr><td class="span-swiper"> </td></tr> </table></td> <td class="daughter daughter-right"><table class="constituent binaryrule" data-cat="S[dcl]\NP"> <tr class="daughters"> <td class="daughter daughter-left"><table class="constituent binaryrule" data-cat="S[dcl]\NP"> <tr class="daughters"> <td class="daughter daughter-left"><table class="constituent lex" data-token="is" data-from="4" data-to="6" data-cat="(S[dcl]\NP)/NP"> <tr><td class="token">is</td></tr> <tr><td class="cat" tabindex="0">(S[dcl]\NP)/NP</td></tr> <tr><td class="span-swiper"> </td></tr> </table></td> <td class="daughter daughter-right"><table class="constituent unaryrule" data-cat="NP"> <tr class="daughters"><td class="daughter daughter-only"><table class="constituent binaryrule" data-cat="N"> <tr class="daughters"> <td class="daughter daughter-left"><table class="constituent lex" data-token="drie" data-from="7" data-to="11" data-cat="N/N"> <tr><td class="token">drie</td></tr> <tr><td class="cat" tabindex="0">N/N</td></tr> <tr><td class="span-swiper"> </td></tr> </table></td> <td class="daughter daughter-right"><table class="constituent lex" data-token="jaar" data-from="12" data-to="16" data-cat="N"> <tr><td class="token">jaar</td></tr> <tr><td class="cat" tabindex="0">N</td></tr> <tr><td class="span-swiper"> </td></tr> </table></td> </tr> <tr><td colspan="2" class="rulecat"><div class="rulecat"> <div class="cat">N</div> <div class="rule" title="Forward Application">> <sup>0</sup> </div> </div></td></tr> </table></td></tr> <tr><td class="rulecat"><div class="rulecat"> <div class="cat">NP</div> <div class="rule" title="Type Changing"> * </div> </div></td></tr> </table></td> </tr> <tr><td colspan="2" class="rulecat"><div class="rulecat"> <div class="cat">S[dcl]\NP</div> <div class="rule" title="Forward Application">> <sup>0</sup> </div> </div></td></tr> </table></td> <td class="daughter daughter-right"><table class="constituent binaryrule" data-cat="(S[dcl]\NP)\(S[dcl]\NP)"> <tr class="daughters"> <td class="daughter daughter-left"><table class="constituent lex" data-token="sinds" data-from="17" data-to="22" data-cat="((S[dcl]\NP)\(S[dcl]\NP))/S[dcl]"> <tr><td class="token">sinds</td></tr> <tr><td class="cat" tabindex="0">((S[dcl]\NP)\(S[dcl]\NP))/S[dcl]</td></tr> <tr><td class="span-swiper"> </td></tr> </table></td> <td class="daughter daughter-right"><table class="constituent binaryrule" data-cat="S[dcl]"> <tr class="daughters"> <td class="daughter daughter-left"><table class="constituent binaryrule" data-cat="S[dcl]"> <tr class="daughters"> <td class="daughter daughter-left"><table class="constituent unaryrule" data-cat="NP"> <tr class="daughters"><td class="daughter daughter-only"><table class="constituent lex" data-token="Tom" data-from="23" data-to="26" data-cat="N"> <tr><td class="token">Tom</td></tr> <tr><td class="cat" tabindex="0">N</td></tr> <tr><td class="span-swiper"> </td></tr> </table></td></tr> <tr><td class="rulecat"><div class="rulecat"> <div class="cat">NP</div> <div class="rule" title="Type Changing"> * </div> </div></td></tr> </table></td> <td class="daughter daughter-right"><table class="constituent binaryrule" data-cat="S[dcl]\NP"> <tr class="daughters"> <td class="daughter daughter-left"><table class="constituent unaryrule" data-cat="NP"> <tr class="daughters"><td class="daughter daughter-only"><table class="constituent lex" data-token="Boston" data-from="27" data-to="33" data-cat="N"> <tr><td class="token">Boston</td></tr> <tr><td class="cat" tabindex="0">N</td></tr> <tr><td class="span-swiper"> </td></tr> </table></td></tr> <tr><td class="rulecat"><div class="rulecat"> <div class="cat">NP</div> <div class="rule" title="Type Changing"> * </div> </div></td></tr> </table></td> <td class="daughter daughter-right"><table class="constituent binaryrule" data-cat="(S[dcl]\NP)\NP"> <tr class="daughters"> <td class="daughter daughter-left"><table class="constituent lex" data-token="heeft" data-from="34" data-to="39" data-cat="(S[dcl]\NP)/(S[pt]\NP)"> <tr><td class="token">heeft</td></tr> <tr><td class="cat" tabindex="0">(S[dcl]\NP)/(S[pt]\NP)</td></tr> <tr><td class="span-swiper"> </td></tr> </table></td> <td class="daughter daughter-right"><table class="constituent lex" data-token="verlaten" data-from="40" data-to="48" data-cat="(S[pt]\NP)\NP"> <tr><td class="token">verlaten</td></tr> <tr><td class="cat" tabindex="0">(S[pt]\NP)\NP</td></tr> <tr><td class="span-swiper"> </td></tr> </table></td> </tr> <tr><td colspan="2" class="rulecat"><div class="rulecat"> <div class="cat">(S[dcl]\NP)\NP</div> <div class="rule" title="Forward Crossed Composition">> <sup>1</sup><sub>×</sub> </div> </div></td></tr> </table></td> </tr> <tr><td colspan="2" class="rulecat"><div class="rulecat"> <div class="cat">S[dcl]\NP</div> <div class="rule" title="Backward Application">< <sup>0</sup> </div> </div></td></tr> </table></td> </tr> <tr><td colspan="2" class="rulecat"><div class="rulecat"> <div class="cat">S[dcl]</div> <div class="rule" title="Backward Application">< <sup>0</sup> </div> </div></td></tr> </table></td> <td class="daughter daughter-right"><table class="constituent lex" data-token="." data-from="48" data-to="49" data-cat="S[dcl]\S[dcl]"> <tr><td class="token">.</td></tr> <tr><td class="cat" tabindex="0">S[dcl]\S[dcl]</td></tr> <tr><td class="span-swiper"> </td></tr> </table></td> </tr> <tr><td colspan="2" class="rulecat"><div class="rulecat"> <div class="cat">S[dcl]</div> <div class="rule" title="Backward Application">< <sup>0</sup> </div> </div></td></tr> </table></td> </tr> <tr><td colspan="2" class="rulecat"><div class="rulecat"> <div class="cat">(S[dcl]\NP)\(S[dcl]\NP)</div> <div class="rule" title="Forward Application">> <sup>0</sup> </div> </div></td></tr> </table></td> </tr> <tr><td colspan="2" class="rulecat"><div class="rulecat"> <div class="cat">S[dcl]\NP</div> <div class="rule" title="Backward Application">< <sup>0</sup> </div> </div></td></tr> </table></td> </tr> <tr><td colspan="2" class="rulecat"><div class="rulecat"> <div class="cat">S[dcl]</div> <div class="rule" title="Backward Application">< <sup>0</sup> </div> </div></td></tr> </table> </div>
Use with
der.css
.
\begin{tikzpicture}[ampersand replacement=\&] \matrix [column sep=9pt] at (0, 0) { \lexnode*{idm8}{Het}{\catNP}{} \& \lexnode*{idm30}{is}{(\catS[dcl]\?\catNP)/\catNP}{} \& \lexnode*{idm50}{drie}{\catN/\catN}{} \& \lexnode*{idm60}{jaar}{\catN}{} \& \lexnode*{idm79}{sinds}{((\catS[dcl]\?\catNP)\?(\catS[dcl]\?\catNP))/\catS[dcl]}{} \& \lexnode*{idm108}{Tom}{\catN}{} \& \lexnode*{idm126}{Boston}{\catN}{} \& \lexnode*{idm143}{heeft}{(\catS[dcl]\?\catNP)/(\catS[pt]\?\catNP)}{} \& \lexnode*{idm157}{verlaten}{(\catS[pt]\?\catNP)\?\catNP}{} \& \lexnode*{idm169}{.}{\catS[dcl]\?\catS[dcl]}{} \\ }; \binnode*{idm45}{idm50-cat}{idm60-cat}{\FC{0}}{\catN}{} \unnode*{idm42}{idm45}{*}{\catNP}{} \binnode*{idm23}{idm30-cat}{idm42}{\FC{0}}{\catS[dcl]\?\catNP}{} \unnode*{idm105}{idm108-cat}{*}{\catNP}{} \unnode*{idm123}{idm126-cat}{*}{\catNP}{} \binnode*{idm134}{idm143-cat}{idm157-cat}{\FXC{1}}{(\catS[dcl]\?\catNP)\?\catNP}{} \binnode*{idm116}{idm123}{idm134}{\BC{0}}{\catS[dcl]\?\catNP}{} \binnode*{idm100}{idm105}{idm116}{\BC{0}}{\catS[dcl]}{} \binnode*{idm95}{idm100}{idm169-cat}{\BC{0}}{\catS[dcl]}{} \binnode*{idm68}{idm79-cat}{idm95}{\FC{0}}{(\catS[dcl]\?\catNP)\?(\catS[dcl]\?\catNP)}{} \binnode*{idm16}{idm23}{idm68}{\BC{0}}{\catS[dcl]\?\catNP}{} \binnode*{idm3}{idm8-cat}{idm16}{\BC{0}}{\catS[dcl]}{} \end{tikzpicture}
Use with
ccgsym.sty
and
tikzlibraryccgder.code.tex
.
Translations
deu
Es ist drei Jahre her, dass Tom Boston verlassen hat.
eng
It's been three years since Tom left Boston.
ita
Sono tre anni che Tom è andato via da Boston.