CCGWeb - Het is het proberen waard.

Het

(S[dcl]/NP)/(S[adj]\NP)

het

S[dcl]\(S[dcl]/NP)

T ^<

S[dcl]/(S[adj]\NP)

< ¹_×

proberen

(S[adj]\NP)/(S[adj]\NP)

waard

(S[adj]\NP)\NP

> ¹_×

S[dcl]\NP

> ¹_×

S[dcl]

< ⁰

S[dcl]\S[dcl]

S[dcl]

< ⁰

 <div class="der">
<table class="constituent binaryrule" data-cat="S[dcl]">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent binaryrule" data-cat="S[dcl]">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent lex" data-token="Het" data-from="0" data-to="3" data-cat="NP">
<tr><td class="token">Het</td></tr>
<tr><td class="cat" tabindex="0">NP</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent binaryrule" data-cat="S[dcl]\NP">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent binaryrule" data-cat="S[dcl]/(S[adj]\NP)">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent lex" data-token="is" data-from="4" data-to="6" data-cat="(S[dcl]/NP)/(S[adj]\NP)">
<tr><td class="token">is</td></tr>
<tr><td class="cat" tabindex="0">(S[dcl]/NP)/(S[adj]\NP)</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent unaryrule" data-cat="S[dcl]\(S[dcl]/NP)">
<tr class="daughters"><td class="daughter daughter-only"><table class="constituent lex" data-token="het" data-from="7" data-to="10" data-cat="NP">
<tr><td class="token">het</td></tr>
<tr><td class="cat" tabindex="0">NP</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td></tr>
<tr><td class="rulecat"><div class="rulecat">
<div class="cat">S[dcl]\(S[dcl]/NP)</div>
<div class="rule" title="Backward Type Raising">
									T <sup>&lt;</sup>
</div>
</div></td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">S[dcl]/(S[adj]\NP)</div>
<div class="rule" title="Backward Crossed Composition">&lt; <sup>1</sup><sub>×</sub>
</div>
</div></td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent binaryrule" data-cat="(S[adj]\NP)\NP">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent lex" data-token="proberen" data-from="11" data-to="19" data-cat="(S[adj]\NP)/(S[adj]\NP)">
<tr><td class="token">proberen</td></tr>
<tr><td class="cat" tabindex="0">(S[adj]\NP)/(S[adj]\NP)</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent lex" data-token="waard" data-from="20" data-to="25" data-cat="(S[adj]\NP)\NP">
<tr><td class="token">waard</td></tr>
<tr><td class="cat" tabindex="0">(S[adj]\NP)\NP</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">(S[adj]\NP)\NP</div>
<div class="rule" title="Forward Crossed Composition">&gt; <sup>1</sup><sub>×</sub>
</div>
</div></td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">S[dcl]\NP</div>
<div class="rule" title="Forward Crossed Composition">&gt; <sup>1</sup><sub>×</sub>
</div>
</div></td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">S[dcl]</div>
<div class="rule" title="Backward Application">&lt; <sup>0</sup>
</div>
</div></td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent lex" data-token="." data-from="25" data-to="26" data-cat="S[dcl]\S[dcl]">
<tr><td class="token">.</td></tr>
<tr><td class="cat" tabindex="0">S[dcl]\S[dcl]</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">S[dcl]</div>
<div class="rule" title="Backward Application">&lt; <sup>0</sup>
</div>
</div></td></tr>
</table> </div>

Use with der.css.

\begin{tikzpicture}[ampersand replacement=\&]
	\matrix [column sep=9pt] at (0, 0) {
		\lexnode*{idm13}{Het}{\catNP}{} \&
		\lexnode*{idm37}{is}{(\catS[dcl]/\catNP)/(\catS[adj]\?\catNP)}{} \&
		\lexnode*{idm58}{het}{\catNP}{} \&
		\lexnode*{idm75}{proberen}{(\catS[adj]\?\catNP)/(\catS[adj]\?\catNP)}{} \&
		\lexnode*{idm89}{waard}{(\catS[adj]\?\catNP)\?\catNP}{} \&
		\lexnode*{idm101}{.}{\catS[dcl]\?\catS[dcl]}{} \\
	};
	\unnode*{idm51}{idm58-cat}{*}{\catS[dcl]\?(\catS[dcl]/\catNP)}{}
	\binnode*{idm28}{idm37-cat}{idm51}{\BXC{1}}{\catS[dcl]/(\catS[adj]\?\catNP)}{}
	\binnode*{idm66}{idm75-cat}{idm89-cat}{\FXC{1}}{(\catS[adj]\?\catNP)\?\catNP}{}
	\binnode*{idm21}{idm28}{idm66}{\FXC{1}}{\catS[dcl]\?\catNP}{}
	\binnode*{idm8}{idm13-cat}{idm21}{\BC{0}}{\catS[dcl]}{}
	\binnode*{idm3}{idm8}{idm101-cat}{\BC{0}}{\catS[dcl]}{}
\end{tikzpicture}

Use with ccgsym.sty and tikzlibraryccgder.code.tex.

Sentence

Parse

Translations