CCGWeb - Hoe zeg je dat in het Nederlands?

Hoe

S[wq]/S[q]

zeg

(S[q]/(S[b]\NP))/NP

S[q]/(S[b]\NP)

> ⁰

dat

(S[b]\NP)/PP

PP/NP

het

NP/N

Nederlands

> ⁰

S[b]\NP

> ⁰

S[q]

> ⁰

S[q]\S[q]

S[q]

< ⁰

S[wq]

> ⁰

 <div class="der">
<table class="constituent binaryrule" data-cat="S[wq]">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent lex" data-token="Hoe" data-from="0" data-to="3" data-cat="S[wq]/S[q]">
<tr><td class="token">Hoe</td></tr>
<tr><td class="cat" tabindex="0">S[wq]/S[q]</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent binaryrule" data-cat="S[q]">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent binaryrule" data-cat="S[q]">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent binaryrule" data-cat="S[q]/(S[b]\NP)">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent lex" data-token="zeg" data-from="4" data-to="7" data-cat="(S[q]/(S[b]\NP))/NP">
<tr><td class="token">zeg</td></tr>
<tr><td class="cat" tabindex="0">(S[q]/(S[b]\NP))/NP</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent lex" data-token="je" data-from="8" data-to="10" data-cat="NP">
<tr><td class="token">je</td></tr>
<tr><td class="cat" tabindex="0">NP</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">S[q]/(S[b]\NP)</div>
<div class="rule" title="Forward Application">&gt; <sup>0</sup>
</div>
</div></td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent binaryrule" data-cat="S[b]\NP">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent lex" data-token="dat" data-from="11" data-to="14" data-cat="(S[b]\NP)/PP">
<tr><td class="token">dat</td></tr>
<tr><td class="cat" tabindex="0">(S[b]\NP)/PP</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent binaryrule" data-cat="PP">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent lex" data-token="in" data-from="15" data-to="17" data-cat="PP/NP">
<tr><td class="token">in</td></tr>
<tr><td class="cat" tabindex="0">PP/NP</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent binaryrule" data-cat="NP">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent lex" data-token="het" data-from="18" data-to="21" data-cat="NP/N">
<tr><td class="token">het</td></tr>
<tr><td class="cat" tabindex="0">NP/N</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent lex" data-token="Nederlands" data-from="22" data-to="32" data-cat="N">
<tr><td class="token">Nederlands</td></tr>
<tr><td class="cat" tabindex="0">N</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">NP</div>
<div class="rule" title="Forward Application">&gt; <sup>0</sup>
</div>
</div></td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">PP</div>
<div class="rule" title="Forward Application">&gt; <sup>0</sup>
</div>
</div></td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">S[b]\NP</div>
<div class="rule" title="Forward Application">&gt; <sup>0</sup>
</div>
</div></td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">S[q]</div>
<div class="rule" title="Forward Application">&gt; <sup>0</sup>
</div>
</div></td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent lex" data-token="?" data-from="32" data-to="33" data-cat="S[q]\S[q]">
<tr><td class="token">?</td></tr>
<tr><td class="cat" tabindex="0">S[q]\S[q]</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">S[q]</div>
<div class="rule" title="Backward Application">&lt; <sup>0</sup>
</div>
</div></td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">S[wq]</div>
<div class="rule" title="Forward Application">&gt; <sup>0</sup>
</div>
</div></td></tr>
</table> </div>

Use with der.css.

\begin{tikzpicture}[ampersand replacement=\&]
	\matrix [column sep=9pt] at (0, 0) {
		\lexnode*{idm8}{Hoe}{\catS[wq]/\catS[q]}{} \&
		\lexnode*{idm37}{zeg}{(\catS[q]/(\catS[b]\?\catNP))/\catNP}{} \&
		\lexnode*{idm51}{je}{\catNP}{} \&
		\lexnode*{idm66}{dat}{(\catS[b]\?\catNP)/\catPP}{} \&
		\lexnode*{idm83}{in}{\catPP/\catNP}{} \&
		\lexnode*{idm98}{het}{\catNP/\catN}{} \&
		\lexnode*{idm108}{Nederlands}{\catN}{} \&
		\lexnode*{idm116}{?}{\catS[q]\?\catS[q]}{} \\
	};
	\binnode*{idm28}{idm37-cat}{idm51-cat}{\FC{0}}{\catS[q]/(\catS[b]\?\catNP)}{}
	\binnode*{idm93}{idm98-cat}{idm108-cat}{\FC{0}}{\catNP}{}
	\binnode*{idm78}{idm83-cat}{idm93}{\FC{0}}{\catPP}{}
	\binnode*{idm59}{idm66-cat}{idm78}{\FC{0}}{\catS[b]\?\catNP}{}
	\binnode*{idm23}{idm28}{idm59}{\FC{0}}{\catS[q]}{}
	\binnode*{idm18}{idm23}{idm116-cat}{\BC{0}}{\catS[q]}{}
	\binnode*{idm3}{idm8-cat}{idm18}{\FC{0}}{\catS[wq]}{}
\end{tikzpicture}

Use with ccgsym.sty and tikzlibraryccgder.code.tex.

Sentence

Parse

Translations