Sentence


Parse

Tom
N
 
NP
*
doet
((S[dcl]\NP)/PP)/NP
 
zijn
NP/(N/PP)
 
sokken
N/PP
 
NP
> 0
(S[dcl]\NP)/PP
> 0
aan
PP
 
S[dcl]\NP
> 0
S[dcl]
< 0
.
S[dcl]\S[dcl]
 
S[dcl]
< 0

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