Sentence


Parse

Tom
N
 
NP
*
heeft
(S[dcl]\NP)/(S[b]\NP)
 
de
NP/N
 
ervaring
N
 
N/(N\N)
T >
die
(N\N)/(S[dcl]\NP)
 
N/(S[dcl]\NP)
> 1
NP/(S[dcl]\NP)
> 1
nodig
(S[b]\NP)\NP
 
(S[b]\NP)/(S[dcl]\NP)
< 1×
is
(S[dcl]\NP)/PP
 
om
PP/NP
 
de
NP/N
 
klus
N
 
te
(S[dcl]/NP)/(S[b]\NP)
 
klaren
S[b]\NP
 
S[dcl]/NP
> 0
N\N
*
N
< 0
NP
> 0
PP
> 0
S[dcl]\NP
> 0
S[b]\NP
> 0
S[dcl]\NP
> 0
S[dcl]
< 0
.
S[dcl]\S[dcl]
 
S[dcl]
< 0

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