Sentence


Parse

Werkt
(S[q]/NP)/NP
 
u
NP
 
S[q]/NP
> 0
's
S[q]\S[q]
 
S[q]/NP
< 1×
maandags
NP
 
S[q]
> 0
?
S[q]\S[q]
 
S[q]
< 0

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