Sentence


Parse

É
S[dcl]/S[dcl]
 
um
N
 
prazer
NP/N
 
N
 
NP
> 0
S[dcl]/(S[dcl]\NP)
T >
-
(S[dcl]\NP)/NP
 
S[dcl]/NP
> 1
N\N
*
N
< 0
NP
*
lo
NP
 
NP/(NP\NP)
T >
novamente
(S[dcl]\NP)\NP
 
(S[dcl]\NP)/(NP\NP)
< 1×
.
NP\NP
 
S[dcl]\NP
> 0
S[dcl]
< 0
S[dcl]
> 0

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