Sentence


Parse

A
(S[dcl]/S[dcl])/NP
 
senhora
S[dcl]/NP
 
pode
NP/N
 
nos
N
 
NP
> 0
S[dcl]
> 0
S[dcl]\(S[dcl]/S[dcl])
T <
S[dcl]/NP
< 1×
ajudar
N
 
NP
*
?
NP\NP
 
NP
< 0
S[dcl]
> 0

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