Sentence


Parse

A
(S[dcl]/S[dcl])/NP
 
bom
N
 
NP
*
NP/(NP\NP)
T >
entendedor
S[dcl]\NP
 
S[dcl]/(NP\NP)
< 1×
,
NP\NP
 
S[dcl]
> 0
S[dcl]\(S[dcl]/S[dcl])
T <
S[dcl]/NP
< 1×
meia
N/N
 
palavra
N/N
 
basta
N
 
N
> 0
N
> 0
NP
*
S[dcl]
> 0
.
S[dcl]\S[dcl]
 
S[dcl]
< 0

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