Sentence


Parse

A
(S[dcl]/S[dcl])/NP
 
ducha
N
 
NP
*
S[dcl]/S[dcl]
> 0
está
S[dcl]/NP
 
quebrada
N
 
NP
*
S[dcl]
> 0
.
S[dcl]\S[dcl]
 
S[dcl]
< 0
S[dcl]
> 0

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