Sentence


Parse

Deixa
S[dcl]/NP
 
-
(NP\NP)/NP
 
(S[dcl]\NP)/NP
> n
me
NP
 
S[dcl]/(S[dcl]\NP)
T >
em
N/N
 
paz
N
 
N
> 0
NP
*
(S[dcl]\NP)\((S[dcl]\NP)/NP)
T <
S[dcl]\((S[dcl]\NP)/NP)
> 1×
S[dcl]
< 0
.
S[dcl]\S[dcl]
 
S[dcl]
< 0

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