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Estou
S[dcl]/(S[pss]\NP)
 
muito
S[pss]\NP
 
S[dcl]
> 0
contente
((S[b]\NP)/PP)/NP
 
por
PP/NP
 
voltar
N
 
NP
*
PP
> 0
(S[b]\NP)\((S[b]\NP)/PP)
T <
(S[b]\NP)/NP
< 1×
a
(S[to]\NP)/(S[b]\NP)
 
N
 
NP
*
(S[b]\NP)\((S[b]\NP)/NP)
T <
-
((S[b]\NP)\(S[b]\NP))/NP
 
lo
NP
 
(S[b]\NP)\(S[b]\NP)
> 0
(S[b]\NP)\((S[b]\NP)/NP)
< 1
(S[to]\NP)\((S[b]\NP)/NP)
> 1×
S[to]\NP
< 0
S[dcl]/S[dcl]
*
.
S[dcl]\S[dcl]
 
S[dcl]\S[dcl]
> 1×
S[dcl]
< 0

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