Sentence


Parse

Eu
N
 
NP
*
lembro
S[dcl]\NP
 
(S[dcl]\NP)/((S[dcl]\NP)\(S[dcl]\NP))
T >
que
N
 
NP
*
S[dcl]/(S[dcl]\NP)
T >
a
((S[dcl]\NP)\(S[dcl]\NP))/NP
 
encontrei
N
 
NP
*
(S[dcl]\NP)\(S[dcl]\NP)
> 0
S[dcl]\(S[dcl]\NP)
> 1×
S[dcl]/((S[dcl]\NP)\(S[dcl]\NP))
< 1×
em
((S[dcl]\NP)\(S[dcl]\NP))/S[dcl]
 
algum
(S[dcl]\NP)/NP
 
lugar
N
 
NP
*
S[dcl]\NP
> 0
((S[dcl]\NP)\(S[dcl]\NP))\NP
> 1×
S[dcl]\NP
> 1×
S[dcl]
< 0
.
S[dcl]\S[dcl]
 
S[dcl]
< 0

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