Sentence


Parse

Falar
S[dcl]/S[dcl]
 
inglês
(S[dcl]\NP)/NP
 
é
NP
 
S[dcl]/(S[dcl]\NP)
T >
difícil
N
 
NP
*
(S[dcl]\NP)\((S[dcl]\NP)/NP)
T <
S[dcl]\((S[dcl]\NP)/NP)
> 1×
S[dcl]
< 0
.
S[dcl]\S[dcl]
 
S[dcl]
< 0
S[dcl]
> 0

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