Sentence


Parse

Isso
N
 
NP
*
não
(S[dcl]\NP)/NP
 
deveria
S[pss]\NP
 
S[dcl]/S[dcl]
*
ser
N/N
 
um
N/N
 
problema
N
 
N
> 0
N
> 0
NP
*
(S[dcl]\NP)\((S[dcl]\NP)/NP)
T <
(S[dcl]\NP)\((S[dcl]\NP)/NP)
> n
S[dcl]\NP
< 0
S[dcl]
< 0
.
S[dcl]\S[dcl]
 
S[dcl]
< 0

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