Sentence


Parse

Minha
NP/N
 
memória
N/N
 
de
N/N
 
curto
N
 
N
> 0
N
> 0
prazo
(N\N)/NP
 
está
N
 
NP
*
N\N
> 0
N
< 0
NP
> 0
NP/(NP\NP)
T >
se
(S[dcl]/S[dcl])/S[dcl]
 
tornando
S[dcl]/NP
 
mais
N
 
NP
*
e
(NP\NP)/NP
 
mais
N
 
NP
*
NP\NP
> 0
NP
< 0
S[dcl]
> 0
S[dcl]/S[dcl]
> 0
curta
S[dcl]\NP
 
S[dcl]\NP
> 1×
S[dcl]/(NP\NP)
< 1×
.
NP\NP
 
S[dcl]
> 0

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