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O
S[dcl]/S[dcl]
 
que
(S[dcl]/S[dcl])\(S[dcl]/S[dcl])
 
S[dcl]/S[dcl]
< 0
te
NP
 
mantém
(S[dcl]\NP)/NP
 
acordado
(S[ng]\NP)/NP
 
até
NP/N
 
tão
N
 
NP
> 0
S[ng]\NP
> 0
S[dcl]/S[dcl]
*
tarde
N
 
NP
*
(S[dcl]\NP)\((S[dcl]\NP)/NP)
T <
(S[dcl]\NP)\((S[dcl]\NP)/NP)
> n
S[dcl]\NP
< 0
S[dcl]
< 0
S[dcl]
> 0
?
S[dcl]\S[dcl]
 
S[dcl]
< 0

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