Sentence


Parse

O
S[dcl]/S[dcl]
 
policial
NP/N
 
está
(S[dcl]\NP)/NP
 
usando
(S[ng]\NP)/NP
 
uma
N
 
NP
*
S[ng]\NP
> 0
S[dcl]/S[dcl]
*
máscara
N/N
 
de
N
 
N
> 0
NP
*
(S[dcl]\NP)\((S[dcl]\NP)/NP)
T <
(S[dcl]\NP)\((S[dcl]\NP)/NP)
> n
S[dcl]\NP
< 0
S[dcl]/N
< 1×
gás
N
 
S[dcl]
> 0
.
S[dcl]\S[dcl]
 
S[dcl]
< 0
S[dcl]
> 0

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