Sentence


Parse

O
S[dcl]/S[dcl]
 
que
(S[dcl]\NP)/(S[dcl]\NP)
 
está
(S[dcl]\NP)/PP
 
a
PP/NP
 
(S[dcl]\NP)/NP
> 1
(S[dcl]\NP)/NP
> 1
senhora
N
 
NP
*
S[dcl]/(S[dcl]\NP)
T >
lendo
N
 
NP
*
?
NP\NP
 
NP
< 0
(S[dcl]\NP)\((S[dcl]\NP)/NP)
T <
S[dcl]\((S[dcl]\NP)/NP)
> 1×
S[dcl]
< 0
S[dcl]
> 0

Use with der.css.

Use with ccgsym.sty and tikzlibraryccgder.code.tex.


Translations